(\frac{2}{3})^3 = \frac{2}{3} \cdot \frac{2}{3} \cdot \frac{2}{3} \ (\frac{5}{7})^2 = \ (\frac{3}{2})^2 = \ (\frac{5}{4})^2 \ (\frac{8}{9})^2 \ (\frac{3}{7})^2 \ (\frac{9}{6})^2

Para resolver as potências de frações, elevamos tanto o numerador quanto o denominador ao expoente indicado.

1. $\left(\frac{2}{3}\right)^3 = \frac{2^3}{3^3} = \frac{8}{27}$
2. $\left(\frac{5}{7}\right)^2 = \frac{5^2}{7^2} = \frac{25}{49}$
3. $\left(\frac{3}{2}\right)^2 = \frac{3^2}{2^2} = \frac{9}{4}$
4. $\left(\frac{5}{4}\right)^2 = \frac{5^2}{4^2} = \frac{25}{16}$
5. $\left(\frac{8}{9}\right)^2 = \frac{8^2}{9^2} = \frac{64}{81}$
6. $\left(\frac{3}{7}\right)^2 = \frac{3^2}{7^2} = \frac{9}{49}$
7. $\left(\frac{9}{6}\right)^2 = \frac{9^2}{6^2} = \frac{81}{36} = \frac{9}{4}$ (simplificado)